(3x)^(1/2)+(x)^(1/4)=6

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Solution for (3x)^(1/2)+(x)^(1/4)=6 equation:


D( x )

x < 0

3*x < 0

x < 0

3*x < 0

3*x < 0

3*x+0 < 0 // - 0

3*x < 0 // : 3

x < 0/3

x < 0

x in <0:+oo)

(3*x)^(1/2)+x^(1/4) = 6 // - 6

(3*x)^(1/2)+x^(1/4)-6 = 0

3^(1/2)*x^(1/2)+x^(1/4)-6 = 0

t_1 = x^(1/4)

3^(1/2)*t_1^2+1*t_1^1-6 = 0

3^(1/2)*t_1^2+t_1-6 = 0

DELTA = 1^2-(-6*4*3^(1/2))

DELTA = 24*3^(1/2)+1

DELTA = 42.56921944

DELTA > 0

t_1 = ((24*3^(1/2)+1)^(1/2)-1)/(2*3^(1/2)) or t_1 = (-(24*3^(1/2)+1)^(1/2)-1)/(2*3^(1/2))

t_1 = ((24*3^(1/2)+1)^(1/2)-1)/(2*3^(1/2)) or t_1 = (-1/2)*3^(-1/2)*((24*3^(1/2)+1)^(1/2)+1)

t_1 = (-1/2)*3^(-1/2)*((24*3^(1/2)+1)^(1/2)+1)

x^(1/4)-((-1/2)*3^(-1/2)*((24*3^(1/2)+1)^(1/2)+1)) = 0

x^(1/4)+(1/2)*((24*3^(1/2)+1)^(1/2)+1)*3^(-1/2) = 0

1*x^(1/4) = -(1/2*((24*3^(1/2)+1)^(1/2)+1)*3^(-1/2)) // : 1

x^(1/4) = -1/2*3^(-1/2)*((24*3^(1/2)+1)^(1/2)+1)

( -1/2*3^(-1/2)*((24*3^(1/2)+1)^(1/2)+1) < 0 i 1/4 in (0:1) ) => x naleu017Cy do O

t_1 = ((24*3^(1/2)+1)^(1/2)-1)/(2*3^(1/2))

x^(1/4)-(((24*3^(1/2)+1)^(1/2)-1)/(2*3^(1/2))) = 0

1*x^(1/4) = ((24*3^(1/2)+1)^(1/2)-1)/(2*3^(1/2)) // : 1

x^(1/4) = ((24*3^(1/2)+1)^(1/2)-1)/(2*3^(1/2))

x^(1/4) = ((24*3^(1/2)+1)^(1/2)-1)/(2*3^(1/2)) // ^ 4

x = (((24*3^(1/2)+1)^(1/2)-1)^4)/144

x = (((24*3^(1/2)+1)^(1/2)-1)^4)/144

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